Integrand size = 21, antiderivative size = 154 \[ \int (a+b \cos (c+d x))^4 \sec ^5(c+d x) \, dx=\frac {\left (3 a^4+24 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))}{8 d}+\frac {4 a b \left (2 a^2+3 b^2\right ) \tan (c+d x)}{3 d}+\frac {a^2 \left (3 a^2+22 b^2\right ) \sec (c+d x) \tan (c+d x)}{8 d}+\frac {5 a^3 b \sec ^2(c+d x) \tan (c+d x)}{6 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^3(c+d x) \tan (c+d x)}{4 d} \]
[Out]
Time = 0.39 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2871, 3110, 3100, 2827, 3852, 8, 3855} \[ \int (a+b \cos (c+d x))^4 \sec ^5(c+d x) \, dx=\frac {5 a^3 b \tan (c+d x) \sec ^2(c+d x)}{6 d}+\frac {4 a b \left (2 a^2+3 b^2\right ) \tan (c+d x)}{3 d}+\frac {a^2 \left (3 a^2+22 b^2\right ) \tan (c+d x) \sec (c+d x)}{8 d}+\frac {a^2 \tan (c+d x) \sec ^3(c+d x) (a+b \cos (c+d x))^2}{4 d}+\frac {\left (3 a^4+24 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))}{8 d} \]
[In]
[Out]
Rule 8
Rule 2827
Rule 2871
Rule 3100
Rule 3110
Rule 3852
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \frac {a^2 (a+b \cos (c+d x))^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac {1}{4} \int (a+b \cos (c+d x)) \left (10 a^2 b+3 a \left (a^2+4 b^2\right ) \cos (c+d x)+b \left (a^2+4 b^2\right ) \cos ^2(c+d x)\right ) \sec ^4(c+d x) \, dx \\ & = \frac {5 a^3 b \sec ^2(c+d x) \tan (c+d x)}{6 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac {1}{12} \int \left (-3 a^2 \left (3 a^2+22 b^2\right )-16 a b \left (2 a^2+3 b^2\right ) \cos (c+d x)-3 b^2 \left (a^2+4 b^2\right ) \cos ^2(c+d x)\right ) \sec ^3(c+d x) \, dx \\ & = \frac {a^2 \left (3 a^2+22 b^2\right ) \sec (c+d x) \tan (c+d x)}{8 d}+\frac {5 a^3 b \sec ^2(c+d x) \tan (c+d x)}{6 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac {1}{24} \int \left (-32 a b \left (2 a^2+3 b^2\right )-3 \left (3 a^4+24 a^2 b^2+8 b^4\right ) \cos (c+d x)\right ) \sec ^2(c+d x) \, dx \\ & = \frac {a^2 \left (3 a^2+22 b^2\right ) \sec (c+d x) \tan (c+d x)}{8 d}+\frac {5 a^3 b \sec ^2(c+d x) \tan (c+d x)}{6 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac {1}{3} \left (4 a b \left (2 a^2+3 b^2\right )\right ) \int \sec ^2(c+d x) \, dx-\frac {1}{8} \left (-3 a^4-24 a^2 b^2-8 b^4\right ) \int \sec (c+d x) \, dx \\ & = \frac {\left (3 a^4+24 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))}{8 d}+\frac {a^2 \left (3 a^2+22 b^2\right ) \sec (c+d x) \tan (c+d x)}{8 d}+\frac {5 a^3 b \sec ^2(c+d x) \tan (c+d x)}{6 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^3(c+d x) \tan (c+d x)}{4 d}-\frac {\left (4 a b \left (2 a^2+3 b^2\right )\right ) \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{3 d} \\ & = \frac {\left (3 a^4+24 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))}{8 d}+\frac {4 a b \left (2 a^2+3 b^2\right ) \tan (c+d x)}{3 d}+\frac {a^2 \left (3 a^2+22 b^2\right ) \sec (c+d x) \tan (c+d x)}{8 d}+\frac {5 a^3 b \sec ^2(c+d x) \tan (c+d x)}{6 d}+\frac {a^2 (a+b \cos (c+d x))^2 \sec ^3(c+d x) \tan (c+d x)}{4 d} \\ \end{align*}
Time = 0.34 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.66 \[ \int (a+b \cos (c+d x))^4 \sec ^5(c+d x) \, dx=\frac {3 \left (3 a^4+24 a^2 b^2+8 b^4\right ) \text {arctanh}(\sin (c+d x))+a \tan (c+d x) \left (9 a \left (a^2+8 b^2\right ) \sec (c+d x)+6 a^3 \sec ^3(c+d x)+32 b \left (3 \left (a^2+b^2\right )+a^2 \tan ^2(c+d x)\right )\right )}{24 d} \]
[In]
[Out]
Time = 4.68 (sec) , antiderivative size = 147, normalized size of antiderivative = 0.95
method | result | size |
derivativedivides | \(\frac {a^{4} \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-4 a^{3} b \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )+6 a^{2} b^{2} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 \tan \left (d x +c \right ) a \,b^{3}+b^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}\) | \(147\) |
default | \(\frac {a^{4} \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-4 a^{3} b \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )+6 a^{2} b^{2} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 \tan \left (d x +c \right ) a \,b^{3}+b^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}\) | \(147\) |
parts | \(\frac {a^{4} \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}+\frac {b^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}-\frac {4 a^{3} b \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )}{d}+\frac {3 a^{2} b^{2} \tan \left (d x +c \right ) \sec \left (d x +c \right )}{d}+\frac {3 a^{2} b^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {4 a \,b^{3} \tan \left (d x +c \right )}{d}\) | \(164\) |
parallelrisch | \(\frac {-36 \left (\frac {3}{4}+\frac {\cos \left (4 d x +4 c \right )}{4}+\cos \left (2 d x +2 c \right )\right ) \left (a^{4}+8 a^{2} b^{2}+\frac {8}{3} b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+36 \left (\frac {3}{4}+\frac {\cos \left (4 d x +4 c \right )}{4}+\cos \left (2 d x +2 c \right )\right ) \left (a^{4}+8 a^{2} b^{2}+\frac {8}{3} b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (256 a^{3} b +192 a \,b^{3}\right ) \sin \left (2 d x +2 c \right )+\left (18 a^{4}+144 a^{2} b^{2}\right ) \sin \left (3 d x +3 c \right )+\left (64 a^{3} b +96 a \,b^{3}\right ) \sin \left (4 d x +4 c \right )+\left (66 a^{4}+144 a^{2} b^{2}\right ) \sin \left (d x +c \right )}{24 d \left (\cos \left (4 d x +4 c \right )+4 \cos \left (2 d x +2 c \right )+3\right )}\) | \(228\) |
risch | \(-\frac {i a \left (9 a^{3} {\mathrm e}^{7 i \left (d x +c \right )}+72 a \,b^{2} {\mathrm e}^{7 i \left (d x +c \right )}-96 b^{3} {\mathrm e}^{6 i \left (d x +c \right )}+33 a^{3} {\mathrm e}^{5 i \left (d x +c \right )}+72 a \,b^{2} {\mathrm e}^{5 i \left (d x +c \right )}-192 a^{2} b \,{\mathrm e}^{4 i \left (d x +c \right )}-288 b^{3} {\mathrm e}^{4 i \left (d x +c \right )}-33 a^{3} {\mathrm e}^{3 i \left (d x +c \right )}-72 a \,b^{2} {\mathrm e}^{3 i \left (d x +c \right )}-256 a^{2} b \,{\mathrm e}^{2 i \left (d x +c \right )}-288 b^{3} {\mathrm e}^{2 i \left (d x +c \right )}-9 a^{3} {\mathrm e}^{i \left (d x +c \right )}-72 a \,b^{2} {\mathrm e}^{i \left (d x +c \right )}-64 a^{2} b -96 b^{3}\right )}{12 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{4}}-\frac {3 a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{8 d}-\frac {3 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) b^{2}}{d}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) b^{4}}{d}+\frac {3 a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{8 d}+\frac {3 a^{2} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) b^{2}}{d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) b^{4}}{d}\) | \(353\) |
norman | \(\frac {\frac {a \left (5 a^{3}-32 a^{2} b +24 a \,b^{2}-32 b^{3}\right ) \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4 d}+\frac {a \left (5 a^{3}+32 a^{2} b +24 a \,b^{2}+32 b^{3}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4 d}+\frac {a \left (45 a^{3}-32 a^{2} b +24 a \,b^{2}+96 b^{3}\right ) \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4 d}+\frac {a \left (45 a^{3}+32 a^{2} b +24 a \,b^{2}-96 b^{3}\right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4 d}+\frac {a \left (69 a^{3}-224 a^{2} b +216 a \,b^{2}-96 b^{3}\right ) \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{12 d}+\frac {a \left (69 a^{3}+224 a^{2} b +216 a \,b^{2}+96 b^{3}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{12 d}+\frac {a \left (165 a^{3}-32 a^{2} b -360 a \,b^{2}-288 b^{3}\right ) \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{12 d}+\frac {a \left (165 a^{3}+32 a^{2} b -360 a \,b^{2}+288 b^{3}\right ) \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{12 d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{4} \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{4}}-\frac {\left (3 a^{4}+24 a^{2} b^{2}+8 b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{8 d}+\frac {\left (3 a^{4}+24 a^{2} b^{2}+8 b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{8 d}\) | \(424\) |
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 163, normalized size of antiderivative = 1.06 \[ \int (a+b \cos (c+d x))^4 \sec ^5(c+d x) \, dx=\frac {3 \, {\left (3 \, a^{4} + 24 \, a^{2} b^{2} + 8 \, b^{4}\right )} \cos \left (d x + c\right )^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, {\left (3 \, a^{4} + 24 \, a^{2} b^{2} + 8 \, b^{4}\right )} \cos \left (d x + c\right )^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (32 \, a^{3} b \cos \left (d x + c\right ) + 6 \, a^{4} + 32 \, {\left (2 \, a^{3} b + 3 \, a b^{3}\right )} \cos \left (d x + c\right )^{3} + 9 \, {\left (a^{4} + 8 \, a^{2} b^{2}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{48 \, d \cos \left (d x + c\right )^{4}} \]
[In]
[Out]
Timed out. \[ \int (a+b \cos (c+d x))^4 \sec ^5(c+d x) \, dx=\text {Timed out} \]
[In]
[Out]
none
Time = 0.21 (sec) , antiderivative size = 187, normalized size of antiderivative = 1.21 \[ \int (a+b \cos (c+d x))^4 \sec ^5(c+d x) \, dx=\frac {64 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} a^{3} b - 3 \, a^{4} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 72 \, a^{2} b^{2} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 24 \, b^{4} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 192 \, a b^{3} \tan \left (d x + c\right )}{48 \, d} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 360 vs. \(2 (144) = 288\).
Time = 0.34 (sec) , antiderivative size = 360, normalized size of antiderivative = 2.34 \[ \int (a+b \cos (c+d x))^4 \sec ^5(c+d x) \, dx=\frac {3 \, {\left (3 \, a^{4} + 24 \, a^{2} b^{2} + 8 \, b^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 3 \, {\left (3 \, a^{4} + 24 \, a^{2} b^{2} + 8 \, b^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) + \frac {2 \, {\left (15 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 96 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 72 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 96 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 9 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 160 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 72 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 288 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 9 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 160 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 72 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 288 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 15 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 96 \, a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 72 \, a^{2} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 96 \, a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{4}}}{24 \, d} \]
[In]
[Out]
Time = 18.02 (sec) , antiderivative size = 245, normalized size of antiderivative = 1.59 \[ \int (a+b \cos (c+d x))^4 \sec ^5(c+d x) \, dx=\frac {\left (\frac {5\,a^4}{4}-8\,a^3\,b+6\,a^2\,b^2-8\,a\,b^3\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\left (\frac {3\,a^4}{4}+\frac {40\,a^3\,b}{3}-6\,a^2\,b^2+24\,a\,b^3\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (\frac {3\,a^4}{4}-\frac {40\,a^3\,b}{3}-6\,a^2\,b^2-24\,a\,b^3\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (\frac {5\,a^4}{4}+8\,a^3\,b+6\,a^2\,b^2+8\,a\,b^3\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}+\frac {\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (\frac {3\,a^4}{4}+6\,a^2\,b^2+2\,b^4\right )}{d} \]
[In]
[Out]